Chapter 17 & 18

Direct Current & Circuits

Example 18-6 Solution

First apply the node rule at c and b:

c

b

These two equation are identical so we need only one of them to solve the problem.

Next we apply the loop rule to the loops in the circuit. There are three different loops in the circuit, abcda, befcb, and aefda. The third equation does gives any new information so we will use the first two loops.

abcda

befcb

We now have three equations and three unknowns to solve. If we take one of the current equations and substitute it in the first loop equation we can get rid of . This gives:

Then simplifying the equation:

Now we can use elimination to find . Simplifying the befcb equation and dividing by 2 leads to:

Then subtracting the last two equations gives us:

Using this value for in the equation above we can obtain :

Finally, using one of the current equations:

Since, and we picked the wrong direction for the current.

Find the potential difference between points b and c.

2 V

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